Score : 400 points
You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?
Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.
When a positive integer A divides a positive integer B, A is said to a divisor of B. For example, 6 has four divisors: 1, 2, 3 and 6.
Input is given from Standard Input in the following format:
N
Print the number of the Shichi-Go numbers that are divisors of N!.
9
0
There are no Shichi-Go numbers among the divisors of 9! = 1 \times 2 \times ... \times 9 = 362880.
10
1
There is one Shichi-Go number among the divisors of 10! = 3628800: 32400.
100
543