Score : 600 points
Given is a tree T with N vertices. The i-th edge connects Vertex A_i and B_i (1 \leq A_i,B_i \leq N).
Now, each vertex is painted black with probability 1/2 and white with probability 1/2, which is chosen independently from other vertices. Then, let S be the smallest subtree (connected subgraph) of T containing all the vertices painted black. (If no vertex is painted black, S is the empty graph.)
Let the holeyness of S be the number of white vertices contained in S. Find the expected holeyness of S.
Since the answer is a rational number, we ask you to print it \bmod 10^9+7, as described in Notes.
When you print a rational number, first write it as a fraction \frac{y}{x}, where x, y are integers, and x is not divisible by 10^9 + 7 (under the constraints of the problem, such representation is always possible).
Then, you need to print the only integer z between 0 and 10^9 + 6, inclusive, that satisfies xz \equiv y \pmod{10^9 + 7}.
Input is given from Standard Input in the following format:
N A_1 B_1 : A_{N-1} B_{N-1}
Print the expected holeyness of S, \bmod 10^9+7.
3 1 2 2 3
125000001
If the vertices 1, 2, 3 are painted black, white, black, respectively, the holeyness of S is 1.
Otherwise, the holeyness is 0, so the expected holeyness is 1/8.
Since 8 \times 125000001 \equiv 1 \pmod{10^9+7}, we should print 125000001.
4 1 2 2 3 3 4
375000003
The expected holeyness is 3/8.
Since 8 \times 375000003 \equiv 3 \pmod{10^9+7}, we should print 375000003.
4 1 2 1 3 1 4
250000002
The expected holeyness is 1/4.
7 4 7 3 1 2 6 5 2 7 1 2 7
570312505